Status: | Obsolete |
---|---|
Series: | - |
RoHS: | Not Compliant |
Prices starting from US$4.08
Distributor | Stock | ||
---|---|---|---|
Farnell
from US$4.08
|
No stock
|
Buy Now |
Block Config | Low Lock |
---|---|
Chipset Validation | N/A |
Density | 256Mb |
FBGA Code | N/A |
Op. Temp. | -40C to +85C |
Part Family | M29EW |
Part Status | Obsolete |
Product Longevity Program | No |
Product Longevity Program Start Date | N/A |
Width | x8/x16 |
FLASH, PARALLEL, 256MBIT, 56TSOP | Farnell |
Where can I find additional details, specifications and documents for a JS28F256M29EWLA?
Additional datasheets, footprints and schematics for JS28F256M29EWLA are listed on our Part Details page. You can also find images and similar parts to JS28F256M29EWLA on this page.
What pricing and inventory information can I view?
Distributor pricing and stock information is available for JS28F256M29EWLA on our Product Comparison page. Access via the 'View Pricing & Stock' button to view JS28F256M29EWLA price breaks, MOQs, lead times, inventory and SKUs from distributors.
Who can I contact for technical support of the product?
Submit any questions directly to the customer support team of the distributor listing the product. For the JS28F256M29EWLA you can contact the distributor directly for product support, shipping queries etc.
Is the JS28F256M29EWLA RoHS compliant?
This part has not been flagged as RoHS Compliant.
Which authorised distributors for JS28F256M29EWLA have stock available?
Authorised distributors including Farnell have stock available or on a lead time for JS28F256M29EWLA.
How do I check stock and lead times for all distributors?
Stock availability and lead times will be displayed for JS28F256M29EWLA often in real-time on the comparison pages.
What if I can't find stock of JS28F256M29EWLA?
You can fill out our help required form which you can use to request a quote for JS28F256M29EWLA from some of our verified obsolescence suppliers. Alternatively, contact us via our web chat in the bottom left of your screen and one of our team will try to help.